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Veteran CutOUT / Overlean?


DjPanJan

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37分鐘前,Chriull說:

我根據這些數字繪製了一個圖表:

順便說一句: @安迪·黃 -100%-0%是什麼意思?退伍軍人謝爾曼(Sherman)顯示的費用百分比?您如何獲取Wh值?

UXXQBni.png

1,

http://www.benzobattery.com/blog/relationship-between-voltage-and-capacity-of-li-ion-battery/

2,

3.5Ah x 50%x 3.82V x 24s x10p = 1604.4WH

單節電池容量為3500mA = 3.5Ah,此時電壓為3.82V,電容為50%,一串24塊電池,共10串並聯

3,

The yellow line is the first long-distance test.

The voltage value at that time corresponds to the number of cells of the electricity meter (eight cells in total).

Although it is not absolutely accurate, the data of the other wheel is almost the same.

 The voltage value relative to the percentage is laboratory data and published on the Internet, I calculated based on this.  The normal calculation is that this wheel is calculated using the working voltage of 3.7V, 3.5Ahx3.7Vx24x10=3108WH (officially marked 3200WH)

4,

Check the official data of sherman, the lowest is 75.6V, so 75.6/24=3.15V

The first published data tilt back at 74.5V, which was later revised to 75.6V

74.5V/24S=3.104V

Edited by Andy Huang
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18 minutes ago, Andy Huang said:

Interesting! Thanks

18 minutes ago, Andy Huang said:

2,

3.5Ah x 50% x 3.82V x 24s x10p =1604.4WH

The capacity of a single battery is 3500mA=3.5Ah, the voltage at this time is 3.82V, the electric capacity is 50%, 24 batteries in a string, a total of 10 strings in parallel

Ah - the 3.82V (in your example) are the fault. As one already has the percentage of the full capacity, one cannot take the acutal voltage anymore but the nominal voltage (3,6V for ncr18650ga)!

So 3.5Ah * 3.6V * 24s * 10p = 3024 Wh is full (100%) capacity. for 50% one has 50% * 3024Wh = 1512Wh...

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This is roughly what it means.  

The main thing I want to express is that after the first two of the eight cells disappeared, the battery has actually used about 70% of the electricity.  

It's not that we mistakenly believe that 75% of the electricity is still inside.

 When the LCD screen shows five grids, there is actually only about 10% of electricity.

The safest way is to read the voltage value to judge the remaining power

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